import ByteMatrix from './ByteMatrix';
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/**
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* @author Satoru Takabayashi
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* @author Daniel Switkin
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* @author Sean Owen
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*/
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export default class MaskUtil {
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private static N1;
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private static N2;
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private static N3;
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private static N4;
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private constructor();
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/**
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* Apply mask penalty rule 1 and return the penalty. Find repetitive cells with the same color and
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* give penalty to them. Example: 00000 or 11111.
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*/
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static applyMaskPenaltyRule1(matrix: ByteMatrix): number;
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/**
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* Apply mask penalty rule 2 and return the penalty. Find 2x2 blocks with the same color and give
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* penalty to them. This is actually equivalent to the spec's rule, which is to find MxN blocks and give a
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* penalty proportional to (M-1)x(N-1), because this is the number of 2x2 blocks inside such a block.
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*/
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static applyMaskPenaltyRule2(matrix: ByteMatrix): number;
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/**
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* Apply mask penalty rule 3 and return the penalty. Find consecutive runs of 1:1:3:1:1:4
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* starting with black, or 4:1:1:3:1:1 starting with white, and give penalty to them. If we
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* find patterns like 000010111010000, we give penalty once.
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*/
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static applyMaskPenaltyRule3(matrix: ByteMatrix): number;
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private static isWhiteHorizontal;
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private static isWhiteVertical;
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/**
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* Apply mask penalty rule 4 and return the penalty. Calculate the ratio of dark cells and give
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* penalty if the ratio is far from 50%. It gives 10 penalty for 5% distance.
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*/
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static applyMaskPenaltyRule4(matrix: ByteMatrix): number;
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/**
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* Return the mask bit for "getMaskPattern" at "x" and "y". See 8.8 of JISX0510:2004 for mask
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* pattern conditions.
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*/
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static getDataMaskBit(maskPattern: number, x: number, y: number): boolean;
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/**
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* Helper function for applyMaskPenaltyRule1. We need this for doing this calculation in both
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* vertical and horizontal orders respectively.
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*/
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private static applyMaskPenaltyRule1Internal;
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}
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